Hi,
I am running OpenSuSe 11.1 and Windows Vista under dual boot and know next to nothing about Linux.
After running into a problem booting my Linux system, I decided to re-install Suse. My drive at that time was laid out as follows
Recovery (F) - 15 GB
Window’s OS (C) - 300 GB
NTFS (D) - 100 GB
Free Space 43.31 GB
1st Linux Swap - 2 GB
2nd Linux Ext3 - 9 GB
3rd Linux Ext3 - 65 GB
NTFS (G) - 100 GB
NTFS (E) - 100 GB
Free Space - 192 GB
Unfortunately, I didn’t chose the 3 Linux Partitions correctly during install and as a result, the install used the 43.31 GB of free space. I then did an fdisk -l and saw the following
Disk /dev/sda: 1000.2 GB, 1000204886016 bytes
255 heads, 63 sectors/track, 121601 cylinders
Units = cylinders of 16065 * 512 = 8225280 bytes
Disk identifier: 0x0fff07e1
Device Boot Start End Blocks Id System
/dev/sda1 1 1959 15728640 7 HPFS/NTFS
/dev/sda2 1960 41155 314841870 7 HPFS/NTFS
/dev/sda3 * 41156 83384 339204442+ f W95 Ext’d (LBA)
/dev/sda4 83385 96515 105474757+ 7 HPFS/NTFS
/dev/sda5 41156 54171 104550988+ 7 HPFS/NTFS
/dev/sda6 60478 60739 2104483+ 82 Linux swap / Solaris
/dev/sda7 60740 61841 8851783+ 83 Linux
/dev/sda8 61842 70294 67898691 83 Linux
/dev/sda9 70295 83384 105145393+ 7 HPFS/NTFS
/dev/sda10 54172 55352 9486351 83 Linux
/dev/sda11 55353 60477 41166531 83 Linux
Partition table entries are not in disk order
Disk /dev/sdb: 1500.3 GB, 1500301909504 bytes
1 heads, 63 sectors/track, 46512335 cylinders
Units = cylinders of 63 * 512 = 32256 bytes
Disk identifier: 0x5324add6
Device Boot Start End Blocks Id System
/dev/sdb1 2 46512256 1465136032+ 7 HPFS/NTFS
Disk /dev/sdc: 2047 MB, 2047681024 bytes
64 heads, 63 sectors/track, 991 cylinders
Units = cylinders of 4032 * 512 = 2064384 bytes
Disk identifier: 0x00000000
Device Boot Start End Blocks Id System
/dev/sdc1 1 991 1997733+ 6 FAT16
So now I have a functioning Windows system, a new, functioning Linux system, and a broken Linux system which, when you try to boot it, comes up in grub.
Executing grub from the healthy Linux system seem so confirm that there are two Linux systems installed on the drive, since, when I execute find /boot/grub/menu.lst, it lists both (hd0,6) and (hd0,9).
Based on what I see in the /boot/grub/menu.lst file, it is (hd0,9) that is healthy –
Modified by YaST2. Last modification on Tue Nov 6 18:38:06 UTC 2012
default 0
timeout 8
##YaST - generic_mbr
gfxmenu (hd0,9)/boot/message
##YaST - activate
###Don’t change this comment - YaST2 identifier: Original name: windows 2###
title Windows Vista
rootnoverify (hd0,1)
chainloader +1
###Don’t change this comment - YaST2 identifier: Original name: linux###
title openSUSE 11.1 - 2.6.27.7-9
root (hd0,9)
kernel /boot/vmlinuz-2.6.27.7-9-default root=/dev/disk/by-id/ata-ST31000528AS_9VP771VT-part10 resume=/dev/disk/by-id/ata-ST31000528AS_9VP771VT-part6 splash=silent showopts vga=0x31a
initrd /boot/initrd-2.6.27.7-9-default
###Don’t change this comment - YaST2 identifier: Original name: failsafe###
title Failsafe – openSUSE 11.1 - 2.6.27.7-9
root (hd0,9)
kernel /boot/vmlinuz-2.6.27.7-9-default root=/dev/disk/by-id/ata-ST31000528AS_9VP771VT-part10 showopts ide=nodma apm=off noresume edd=off powersaved=offnohz=off highres=off processor.max_cstate=1 x11failsafe vga=0x31a
initrd /boot/initrd-2.6.27.7-9-default
###Don’t change this comment - YaST2 identifier: Original name: SUSE LINUX (/dev/sda7)###
title SUSE LINUX (/dev/sda7)
rootnoverify (hd0,6)
chainloader +1
In any case, I am wondering how to uninstall the two Linux systems so that I may make a clean install thereafter. I have seen multiple threads out there advising how to do this, but there seems to be some disagreement as to which is the best way.
I would appreciate any help at all here,
Thanks,
s660117