I’ve set a script up which is called using cron every hour or so. The script it runs is a simple affair - just rsyncs some files from A to B.
It works and currently writes the output to a log file.
Problem is, this file gets rather large and I want to “rotate” it.
Currently, to create the log file, it has these lines in the script:-
#!/bin/sh
LOG_FILE=/home/badger_fruit/my-backup.log
echo >> $LOG_FILE
echo "------------------------------" >> $LOG_FILE
date >> $LOG_FILE
echo "------------------------------" >> $LOG_FILE
How can I get it to create a filename based on the date?
For example, on Monday 01 January 2009, the file should be called 2009-01-01-backup.log; he following day to be 2009-01-02-backup.log and so on.
I look forward to any / all suggestions!
Thanks
Rich
LOG_FILE=/home/badger_fruit/$(date ‘+%Y-%m-%d’)-backup.log
Also change the first line to #!/bin/bash since $() is a bash construct, not sh, but you will get away with it on Linux because bash is the standard sh.
Be careful with the % if you put this line in a crontab. See man crontab for why % is special.
Wow, quick reply Ken, thanks!
I’ll give it a g now …
(by the way, this is not going in the crontab file, the crontab calls this file)
badger_fruit@bgrsvr-y:~/bin> crontab -l
DO NOT EDIT THIS FILE - edit the master and reinstall.
(/tmp/crontab.XXXXEk688r installed on Sun Dec 21 12:12:33 2008)
(Cron version V5.0 – $Id: crontab.c,v 1.12 2004/01/23 18:56:42 vixie Exp $)
30 * * * * /home/badger_fruit/bin/backup-script
>>> EDIT >>>>
Just made that change and it’s worked 100% - nice one, thank you!!!