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Thread: How use reg expr to find substring up to indexOf string?

  1. #1
    6tr6tr NNTP User

    Default How use reg expr to find substring up to indexOf string?


    I have a bunch of files named "xxxx.idl". I need to pull out the
    filename without the extension via regualr expression (in the above
    example, that would be "xxxx"). How do I do this?


    Example:

    File: "SomeFile.idl"
    Result of Reg Expr: "SomeFile"


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    6tr6tr
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  2. #2
    hcvv NNTP User

    Default Re: How use reg expr to find substring up to indexOf string?


    Must it be a reg expr or is that just another way to say what you want
    as output?


    Code:
    --------------------
    cd <dir-where-they-are>
    for FILE in *.idl
    do echo "${FILE%.idl}"
    done
    --------------------


    There is no reg exp in this solution, just file name expansion and
    parameter value cutoff, so you may not be happy with this.


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  3. #3
    rmjones101 NNTP User

    Default Re: How use reg expr to find substring up to indexOf string?


    If you just need it for a script, you can simply...

    Code:
    --------------------
    ls *.idl | awk -F. '{print $1}'
    --------------------

    That will list all files ending in .idl, then awk will output the first
    field using the period '.' as the field separator. From there you can
    redirect the output wherever you wish. ie.. to a file named 'outputfile'
    would be...

    Code:
    --------------------
    ls *.idl | awk -F. '{print $1}' > outputfile
    --------------------


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